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In the above questions, if the polarity of E_(2) is reversed, then |
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Answer» current in both ammeters will FLOW in same direction `I_(2) = (E_(2))/(R_(2))` and `I_(1) = (E_(1) + E_(2))/(R_(1))` for `I_(1) = I_(2), R_(1) gt R_(2)` |
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