In the acid base titration [H_3PO_4(0.1 M)+NaOH(0.1 M)] e.m.f of the solution is measured by coupling this electrodes with suitable reference electrode.When alkali is added pH of solution is in acoodance with equation E_(Cell)=E_(Cell)^(@)+0.059 pH For H_3PO_(4) Ka_(1)=10^(-3) , Ka_(2)=10^(-8), Ka_(3)=10^(-13) What is the cell e.m.f at the lind end point of the titration if E_(cell)^(@) at this stage is 1.3805 V.

In the acid base titration [H_3PO_4(0.1 M)+NaOH(0.1 M)] e.m.f of the s

1.	In the acid base titration [H_3PO_4(0.1 M)+NaOH(0.1 M)] e.m.f of the solution is measured by coupling this electrodes with suitable reference electrode.When alkali is added pH of solution is in acoodance with equation E_(Cell)=E_(Cell)^(@)+0.059 pH For H_3PO_(4) Ka_(1)=10^(-3) , Ka_(2)=10^(-8), Ka_(3)=10^(-13) What is the cell e.m.f at the lind end point of the titration if E_(cell)^(@) at this stage is 1.3805 V.
Answer» SOLUTION :`PH=(pKa_2+pKa_3)/2=10.5` `E_(CELL)=E_(cell)^@+0.059 pH=1.3805+0.059xx10.5=2V`