1.

In the acidic medium MnO_(4)^(-) acts as an oixidising agent. MnO_(4) + 8H^(+) + 5e^(-) to Mn^(2+) + 4H_(2)O If the [H^(+)] is reduced to half of its original value, the electrode potential of the half cell MnO_(4), Mn^(2+) |Pt (log 2=0.3010)

Answer»

INCREASES by 14.23 MV
DECREASES by 14.23 mV
increases by 28.46 mV
decreases by 28.46 mV

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