

InterviewSolution
Saved Bookmarks
1. |
In the adjacent rectangle ABCD ∠OCD = 30° . Calculate ∠BOC. What type of triangle is BOC. |
Answer» ∠BCD = 90° [Angle of a rectangle] ∠OCD + ∠OCB = 90° 30° + ∠QCB = 90° ∠OCB = 90° – 30° ∠OCB = 60° ∠OCB = ∠OBC = 60° OC = OB [Diagonals of a rectangle bisect each other] ∴ ∠BOC = 180° – (60° + 60°) = 180° -120° ∠BOC = 60° In Δ BOC, ∠BOC = ∠OBC = ∠OCB = 60° & equiangular triangle ∴ BOC is an equiangular triangle. |
|