In the adjoining figure AB=BC . Find the value of x and y

1.	In the adjoining figure AB=BC . Find the value of x and y
Answer» *Angle* *CAB=Angle ACB* = 65 (*Angles* *opposite* to *equal* *SIDES* *are* *equal* ) *Angle* *CAB* +*Angle* *ACB* +*Angle* *CBA* = *180* (*Triangle* *ABC)* =65+65+y =180 =y+130=180 =y=180-130 =y=50 ________________________________________________________________________ *Angle* *ACB* +Angle *ACD=180(linear PAIR)* =65+Angle *ACD=180 =Angle ACD=180-6*5 =Angle ACD= 115 ________________________________________________________________________ Angle DAC+Angle ACD+Angle ADC=180 (triangle ADC)** =50+115+x=180 =x+165=180 =x=15

Answer»

Angle CAB=Angle ACB = 65 (Angles opposite to equal SIDES are equal )

Angle CAB +Angle ACB +Angle CBA = 180 (Triangle ABC)

=65+65+y =180

=y+130=180

=y=180-130

=y=50

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Angle ACB +Angle ACD=180(linear PAIR)

=65+Angle ACD=180

=Angle ACD=180-65

=Angle ACD= 115

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Angle DAC+Angle ACD+Angle ADC=180 (triangle ADC)

=50+115+x=180

=x+165=180

=x=15

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