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In the adjoining figure. AD and BE and BE are two medians of `DeltaANC.` `IfDF"||"BE,"then prove that"CG=1/4AC.` |
Answer» E is the mid-point of line AC. `thereforeCE=1/2AC" "...(1)` In `DeltaABE,` Since, D is the mid-point of CB and `DF"||"BE` `therefore"F will be the mid-point of CE."" "("coverse of mid-point theorem")` `implies" "CF=1/2CE` `implies" "CF=1/2xx1/2AC" "["from"(1)]` `implies" "CF=1/4AC` |
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