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In the adjoining figure D, E and F are the mid-points of the sides BC, CA and AB of the equilateral `DeltaABC.` Prove that `DeltaDEF` is also an equilateral triangle. |
Answer» In `triangleABC,` F is the mid-point of AB E is the mid point of AC `therefore EF=(1)/(2)BC`(mid point theorem)…(1) Similarly, `FD=(1)/(2)AB" "`(mid point theorem)`" "`…(2) and `ED=(1)/(2)AB" "`(mid-point theorem)`" "`...(3) but AB =BC =CA `implies (1)/(2)AB =(1)/(2)BC=(1)/(2)CA` `implies ED=EF=FD` `implies triangleDEF` is an equilateral triangle. Hence proved. |
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