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In the adjoining figure `PQ_|_BC, AD_|_BC`, then find following ratios: (i( `(A(DeltaPQB))/(A(DeltaPBC))` (ii) `(A(DeltaPBC))/(A(DeltaABC))` (iii) `(A(DeltaABC))/(A(DeltaADC))`(iv) `(A(DeltaADC))/(A(DeltaPQC))` |
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Answer» `DeltaPQB` and `DeltaPBC` have same height `PQ`. Areas of triangles with equal heights are proportional to their corresponding bases. `:.(A(DeltaPQB))/(A(DeltaPBC))=(QB)/(BC)` (iii) `DeltaPBC` and `DeltaABC` have same base BC. Area of triangles with equal bases are propoprtional to their corresponding heights. `:.(A(DeltaPBC))/(A(DeltaABC))=(PQ)/(AD)` (iii) `DeltaBC` and `DeltaADC` have same height `AD`. Areas of triangles with equal heights are proportional to their corresponding bases. `:.(A(DeltaABC))/(A(DeltaADC))=(BC)/(DC)` (iv) Ratio of areas of two triangles is equal to the ratio of the products of their bases and corresponding heights. `:.(A(DeltaADC))/(A(DeltaPQC))=(DCxxAD)/(QCxxPQ)` Ans. (i) `(A(DeltaPQB))/(A(DeltaPBC))=(QB)/(BC)` (ii) `(A(DeltaPBC))/(A(DeltaABC))=(PQ)/(AD)` (iii) `(A(DeltaABC))/(A(DeltaADC))=(BC)/(DC)` (iv) `(A(DeltaADC))/(A(DeltaPQC))=(DCxxAD)/(QCxxPQ)` |
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