1.

In the adjoining figure the impedence of the circuit will be A. `120` ohmB. `50` ohmC. `60` ohmD. `90` ohm

Answer» Correct Answer - C
`i_(L)=90/30=3A. i_(C)=90/20=4.5A`
Net current through circuit `i=i_(C)-i_(L)=1.5A`
`:. Z=V/i=90/1.5=60 Omega`


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