

InterviewSolution
Saved Bookmarks
1. |
In the adjoining figure the impedence of the circuit will be A. `120` ohmB. `50` ohmC. `60` ohmD. `90` ohm |
Answer» Correct Answer - C `i_(L)=90/30=3A. i_(C)=90/20=4.5A` Net current through circuit `i=i_(C)-i_(L)=1.5A` `:. Z=V/i=90/1.5=60 Omega` |
|