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In the arrangement shown in figure, the string has a mass of 4.5 g. How much time will it take for a transverse disturbance produced at the floor to reach the pulley ? Take `g=10ms^-2` . |
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Answer» Correct Answer - `0.02 s` `v=sqrt((T)/(mu))=sqrt((2xx10)/((4.5xx10^(-3))/(2.25)))=100m//s` `t=(L)/(v)=(2)/(100)=0.02sec` |
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