1.

In the beginning the space between the plates of a parallel plate capacitor contains air and thereafter it is filled up with a medium of dielectric constant K. Then ......

Answer»

The electric field and the CAPACITANCE become K TIMES.
The electric field becomes`(1)/(K)` times and the capacitance becomes K times.
The electric field becomes K times and the capacitance becomes `(1)/(K)` times.
The electric field and the capacitance become `(1)/(K)` times

Solution :`E = (E_(0))/(K)` and `C = KC_(0)`
Where `E_(0)` = Electric field for AIR medium.
`C_(0)` = Capacitance of capacitor of air medium.


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