1.

In the Bohr's orbit, what is the ratio of total kinetic energy and the total energy of the electron?

Answer»

`-1`
`-2`
`+1`
`+2`

Solution :Kinetic energy `= 1/2mv^(2)`
POTENTIAL energy `= -(ZE^(2))/R`
But electrostatic force, `(Ze^(2))/(r^(2))=(MV^(2))/r` (centrifugal force)
`THEREFORE` Potential energy `=-mv^(2)`
Total energy `= 1/2mv^(2)-mv^(2)=-1/2mv^(2)`
`therefore` Kinetic energy/total energy `= -1`.


Discussion

No Comment Found

Related InterviewSolutions