1.

In the brown ring complex [Fe(H_2 O)(NO)]SO_4, nitric oxide behaves as

Answer»

`NO^(+)`
NEUTRAL NO molecule
`NO^(-)`
none of these

Solution :No replaces a WATER ligand and by doing so , it is oxidised to a nitrosy ligand , `NO^(+)` and the COMPLEX formed is `[Fe(H_(2)O)_(5) NO]^(2+)`. In this complex iron is PRESENT in +1 oxidation state.


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