1.

In the carbon cycle of fusion,

Answer»

Four `""_(1)H^(1)`fuse to FORM `""_(2)He^(4)` and two POSITRONS
Four `""_(1)H^(1)` fuse to form`""_(2)He^(4)`and two electrons
Two `""_(1)H^(2)`fuse to form `""_(2)He^(4)`
Two `""_(1)H^(2)`fuse to form`""_(2)He^(4)`and two neutrons

Solution :CARBON cycle reaction
`4_(1)H^(1) rarr _(2)H^(4) + 2_(H)e^(0) + 2V + Energy`
Four `""_(1)H^(1)`fuse to form `""_(2)He^(4)` and two positrons


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