1.

In the case of a radio isotope the value of T_(1//2) and lamda are identical in magnitude. The value is

Answer»

0.693
`(0.693)^(1//2)`
`1//0.693`
`(0.693)^(2)`

Solution :For a radioisotope,
half-life period, `T_(1//2)=0.696//LAMDA`
SINCE `T_(1//2)=lamda` (given), `T_(1//2)^(2)=0.693`
`impliesT_(1//2)=0.693^(1//2)`.
Then VALUE of `T_(1//2)` on `lamda` is `0.693^(1//2)`.


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