1.

In the cell reaction Cu(S) + 2 Ag^(+) (aq) to Cu^(2+) (aq) + 2 Ag(s) , E_("cell")^(@) = 0.46 V By doubling the concentration of Cu^(2+) , E_("cell")^(@)is

Answer»

DOUBLED
HALVED
increases but LESS than double
decreases by a small fraction .

SOLUTION :`E_("cell") = E_("cell")^(@) - (RT)/(nF) "ln" ([Cu^(2+)])/([Ag^(+)]^(2))` .
Doubling `[Cu^(2+)]` decreases the EMF by a small fraction .


Discussion

No Comment Found

Related InterviewSolutions