1.

In the cell represented by Pb_(s) |Pb^(2+) (1M) ||Ag^(+)(1M) |Ag_(s) the reducing agents is

Answer»

Pb
`Pb^(2+)`
AG
`Ag^(+)`

SOLUTION :`Pb(s)| Pb^(2+) (1M) ||Ag^(+)(1M)| Ag_(s)`
The compound losing `e^(-)` is called reducing agent.
`Pb to Pb^(2+) + 2E^(-)`


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