1.

In the circuit below, the `AC` source the voltage `V=20cos (omegat)` volts with `omega=2000rad//sec`. The amplitude of the current will be nearest to A. 2AB. 3.3AC. `2//sqrt(5)A`D. `sqrt(5)A`

Answer» Correct Answer - A
`X_(L)=L omega=10 `
`X_(C)=1/(C omega)=10 `
`X_(L)-X_(C)=0`
So, Z=R=6+4 =10
`I_(0)=V_(0)//Z =2A`


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