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In the circuit below, the `AC` source the voltage `V=20cos (omegat)` volts with `omega=2000rad//sec`. The amplitude of the current will be nearest to A. 2AB. 3.3AC. `2//sqrt(5)A`D. `sqrt(5)A` |
Answer» Correct Answer - A `X_(L)=L omega=10 ` `X_(C)=1/(C omega)=10 ` `X_(L)-X_(C)=0` So, Z=R=6+4 =10 `I_(0)=V_(0)//Z =2A` |
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