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In the circuit below, the knee current of ideal zener diode is 10mA. To maintain 5V across the RL, the minimum value of RL is?(a) 120(b) 125(c) 250(d) 100This question was addressed to me in a job interview.Question is from Breakdown Diodes topic in section Semiconductor-Diode Characteristics of Electronic Devices & Circuits |
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Answer» CORRECT CHOICE is (B) 125 To EXPLAIN: Here, IKNEE=10mA, VZ=5V. I=IL+IZ. I= (10-5)/100=50mA Now, 50=10+ILMAX . ILMAX=40mA. RLMIN=5/40mA=125 Ω. |
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