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In the circuit shown below, all the three voltmeters are identical and have very high resistance. Each resistor has the same resistance The voltage of the ideal battery shown is 9 V Find the reading of voltmeter V_(3) (in volts)

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Solution :Taking potential at A to be zero potential at `B=3V` and potential at B'=3V and potential at C=6V so reading of `V_(3)=3V`

LET `V_(D)` be potential of point D then sum of charged reaching point D is zero
`(V_(B)-V_(D))/R_(v_2)+(V_(B')-V_(D))/R_(v_(1))+((V_(C)-V_(D)))/R_(v_(3))=0[R_(v_(1))-R_(v_(1))=R_(v_(3))=R]`
Rightarrow`(3-V_(D))/R+(3-V_(D))/R+(6-V_(D))/R=0`
`Rightarrow 12-3V_(D)=0,V_(D)=4` volts reading of `V_(3)=2` volts


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