In the circuit shown in Fig. A2.3, the battery E_1 has an emf of 12 V and zero internal resistance, while the battery E_2 has an emf of 2 V. If the galvanometer G reads zero, then the value of the resistance Y is

In the circuit shown in Fig. A2.3, the battery E_1 has an emf of 12 V

1.	In the circuit shown in Fig. A2.3, the battery E_1 has an emf of 12 V and zero internal resistance, while the battery E_2 has an emf of 2 V. If the galvanometer G reads zero, then the value of the resistance Y is
Answer» `10 Omega` `100 Omega` ` 500 Omega` `200 Omega` Solution :b. CLEARLY, `E_2 = IY` `2 = 12/(500+Y) Y or 500 + Y = 6Y` or `5Y = 500 or Y = 100 Omega` .

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In the circuit shown in Fig. A2.3, the battery E_1 has an emf of 12 V and zero internal resistance, while the battery E_2 has an emf of 2 V. If the galvanometer G reads zero, then the value of the resistance Y is

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