In the circuit shown in fig. R is a pure resistor, L is an inductor of ngligibe resistance (as compared to R), S is a 100 V , 50 Hz ac source of negligible resistnce. With either kiy (K-1) alone or (K_2) alone closed, the current is (I_0). If the source os changed to 100 V, 100 Hz the current with (K_1) alone closed and with (K_2) alone closed will be, respectively.

In the circuit shown in fig. R is a pure resistor, L is an inductor of

1.	In the circuit shown in fig. R is a pure resistor, L is an inductor of ngligibe resistance (as compared to R), S is a 100 V , 50 Hz ac source of negligible resistnce. With either kiy (K-1) alone or (K_2) alone closed, the current is (I_0). If the source os changed to 100 V, 100 Hz the current with (K_1) alone closed and with (K_2) alone closed will be, respectively.
Answer» `I_(0), (I_(0))/(2)` `I_(0), 2I_(0)` `2I_(0), I_(0)` `2I_(0), (I_(0))/(2)` Solution :Current remains unchanged in R.However, it BECOMES HALF in L, because reactance is doubled on doubling the frequency.

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