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In the circuit shown in figure, if the diode forward voltage drop is 0.3 V, the voltage difference between A and B is |
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Answer» 1.3 V In above figure, calculating changes in electric potential during journey from POINT A to point B, `V_(A)-(0.2xx10^(-3)xx5xx10^(3))-0.3-(0.2xx10^(-3)xx5xx10^(3))=V_(B)` `therefore V_(A)-V_(B)=1+0.3+1=2.3V` |
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