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In the circuit shown in figure neglecting source resistance the voltmeter and ammeter reading will respectively, will be A. `0V,3A`B. `150V,3A`C. `150 V,6A`D. `0V, 8A` |
Answer» Correct Answer - D The voltage `V_(L)` and `V_(C)` are equal and opposites so voltmeter reading will be zero. Also `R=30 Omega, X_(L)=X_(C)=25 Omega` So, `i=V/(sqrt(R^(2)+(X_(L)-X_(C))^(2)))=V/R=240/30=8A` |
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