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In the circuit shown in figure, when the input voltage of the base resistance is 10V, V_(BE) is zero and V_(CE) is also zero. Find the values of I_(B), I_(C ) and beta. |
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Answer» Solution :In the INPUT section, `v_(i)=I_(B)R_(B)+V_(BE)` `therefore 10=(I_(B))(400xx10^(3))+0` `therefore I_(B)=(10)/(400xx10^(3))=0.25xx10^(-4)A` `therefore I_(B)=25xx10^(-6)A=25muA` In the output section, `V_(C C)=I_(C )R_(C )+V_(CE)` `therefore10=I_(C )(3xx10^(3))+0` `therefore I_(C )=(10)/(3xx10^(3))=0.3333xx10^(-2)A` `therefore I_(C )=3333xx10^(-6)A=3333muA` `rArr BETA=(I_(C ))/(I_(B))=(3333)/(25)=133.3` |
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