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in the circuit shown in the figure, each battery is of 5 V and has an internal resistance of 0.2 Omega What is the reading of the ideal voltmeter V |
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Answer» Solution :As the internal resistance of an ideal voltmeter is INFINITE, the resistance of the battery ACROSS which it is connected will not change by its presence as`(1)/(r_(1))=(1)/(r)+(1)/(INFTY)impliesr_(1)=r` Now, as the given eight batteries are discharging in series, i.e `E_(eq) = 8 xx 5 = 40 V` and `r_(eg) = 8 xx 0.2 = 1.6Omega` So, current in the circuit, `I=(E_(eq)/(r_(eq))=(40)/(1.6)=25A` `HENCE, potential difference across the required battery `V=E- Ir = 5-25 xx 0.2 = 0V` |
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