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In the circuit shown R_(1)=R_(2)=10Omega and resistance per unit length of wire PQ=1Omega//cm and length PQ =10 cm if R_(2) is made 20Omega the to get zero deflection in galvanometer. S is midpoint of wire PQ. |
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Answer» The JOCKEY at P can be moved towards right 2 cm  equivalent diagram is as shown is P is moved 2 cm right them `R_(1)=12,R_(3)=3 R_(1)/R_(3)=(R_(2))/(R_(4))` (Hence wheat stone will be balanced) If s is moyed left 5/3 cm then `R_(3)10/3` and `R_(4)=20/3` hence `R_(1)/R_(3)=R_(2)/R_(4)` (hence wheatstone will be balanced) |
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