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In the circuit shown, the resistances are given in ohms and the battery is assumed ideal withh emf equal to 3.0 volts. Q. The current passing through 3 V battery is |
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Answer» 10 mA  The equivalent circuit can be redrawn as shown in figure 1. From figure 1 it is obivious that power dissipated by `R_(1)` is maximum. Potential difference across `R_(2)` is `=(25)/(25+50)xx3` VOLT `=1` volt Therefore potential difference across `R_(3)` or `R_(4)=(20)/(20+30)xx1` volt `=0.4` volt ltbr. the equivalent RESISTANCE of circuit across the cell is `50+25=75` ohms Therefore current through cell is `(3)/(75)xx1000` mA `=40` mA |
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