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In the circuit shown, the switch is shifted from position 1rightarrow 2 at t=0. The switch was initially in position I since a long time. The graph between charge on capacitor C and time 't' is |
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Answer»
 `V_(0)+2Sigma-2iR-q/C=V_(0)` `1=Sigma/R-q/(2RC)` ALSO `i=(DQ)/(DT)` `:. underset(CSigma)OVERSET(q)int (dq)/((Sigma/R-q/(2RC)))=underset0overset(t)intdt` `ln(Sigma/R-q/(2RC))|_(CSigma)^(q)/((-1/(2RC)))=t` `ln ((2SigmaC-q)/(SigmaC))=-t/(2RC)` `q=2SigmaC-SigmaC_(e)^(-t//2RC)` `q=SigmaC(2-e^(-t//2RC))` |
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