In the circuit shown the transformer is ideal with turnration(N_(1))/N_(2)=(5)/(1).The voltage of the source is V_(s) = 300 Volt. The voltage measured across the load resistance R_(L) = 100 Omega is 50 Volt. Find the value of resistance R in the primary circuit.

In the circuit shown the transformer is ideal with turnration(N_(1))/N

1.	In the circuit shown the transformer is ideal with turnration(N_(1))/N_(2)=(5)/(1).The voltage of the source is V_(s) = 300 Volt. The voltage measured across the load resistance R_(L) = 100 Omega is 50 Volt. Find the value of resistance R in the primary circuit.
Answer» ANSWER :`500OMEGA`

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In the circuit shown the transformer is ideal with turnration(N_(1))/N_(2)=(5)/(1).The voltage of the source is V_(s) = 300 Volt. The voltage measured across the load resistance R_(L) = 100 Omega is 50 Volt. Find the value of resistance R in the primary circuit.

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