Saved Bookmarks
| 1. |
In the circuit, the current is to be measured. What is the value of the current if the ammeter shown : (b) is a galvanometer described in (i) but converted to an ammeter by a shunt resistance r_s = 0.02 Omega |
|
Answer» Solution :(b) RESISTANCE of the galvanometer as AMMETER is `(R_(0) r_s)/(R_(G) r_s) = (60Omega XX 0.02 OMEGA)/((60+0.02))= 0.02 Omega` Total resistance `R = 0.02Omega + 3OMEGA = 3.02Omega` Hence, `I = (3)/(302) = 0.99 A` |
|