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In the circuit, various resistance and five batteries are connected as shown in the figure. If point O is earthed, |
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Answer» the current in the battery marked as A is`1//2 A` .  From circuit diagram it is clear `I_1 = (15-5)/6 = 2A, I_2 = (15-10)/2 = 2.5A` Taking BRANCH xM `15 + 2I_3 - 15 = 10 or I_3 = 5A` Taking branch N O `5+5-5I_4 = 0 or I_4 = 2A` In junction `x: I_3 = I_1 + I_2 + I_A` `5 = 2+ 2.5 = I_A or I_A = 1/2 A` In junctionB: ` I_1 + I_A = I_4 + I_B` or `2.0 + 0.5 = 2 + I_(B) or I_(B) = 1/2 A`. |
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