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In the ciruit shown, current throught the resistance 2Omega is i_(1) and current through the resistance 30Omega is i_(2). Fing the ratio (i_(1))/(i_(2)). |
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Answer» Solution :POTENTIALS are indicated in figure Current in `2Omega=(10-(-5))/(2)=(15)/(2)=7.5A` , leftwards Current in `30Omega=(10-(-15))/(30)=(25)/(30)=(5)/(6)A` , downwards `(i_(1))/(i_(2))=9` |
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