1.

In the Column I, a system is described in each option and corresponding time period is given in the column – II, Suitably match them.

Answer»


Solution :(A) In frame of LIFT, effective acceleration due to gravity is `G+(g)/(2)=(3g)/(2)` downwards ` therefore T=2pisqrt((2I)/(3g))`
(B) `KI=mg therefore=(k)/(m)=(g)/(L)`
Constant acceleration of lift has no effect in time period of oscillation.
`therefore T=2pisqrt((m)/(k))=2pisqrt((I)/(g))`
(C)`T=2pisqrt((I)/(mgd))=2pisqrt((((mI)^(2))/(3))/(mg(I)/(2)))=2pisqrt((2I)/(3g))`
`T=2pisqrt((m)/(PAG))=2pisqrt((p//2AI)/(pAg))=2pisqrt((I)/(2g))`


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