1.

In the combustion of 2.0 gm of methane 25 kcal heat is liberated, heat of combustion of methane would be

Answer»

100 kcal
200 kcal
300 kcal
400 kcal

Solution :`CH_(4)+2O_(2)rarrCO_(2)+2H_(2)O`
Molecular weight of `CH_(4)=12+4=16`
`therefore` On the COMBUSTION of 2.0 gm of methane = 25.0 kcal
`therefore` On the combustion of 16.0 gm = `(25xx16)/(2)` = 200 kcal.


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