1.

In the conversion of Br_(2) to BrO_(3)^(-) , the oxidation number of Br changes from

Answer»

zero to + 5
`+1` to `+5`
zero to `-3`
`+2` to `+5`

Solution :`Br_(2)to BrO_(3)^(-)`
Any FREE (unattached) element with no CHARGE has the oxidation STATE of zero.
Let the oxidation number of Br in `BrO_(3)^(-)` be x.
Hence `x+3xx (-2)=-1`or,`x-6=-1`
or,`x=+5`.


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