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In the determination of the internal resistance of acell with apotentiometer, the error in the measurement of the balancing length is pm 1m m . When the cell alone is connected in the circuit, thebalancing length is obtained at 60cm and when the cell is shunted with a resistance of 10 Omega pm 2%, the balancing length is ovtained at 50 cm.The error int he determination ofThe internal resistance ofthe cell is .......... |
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Answer» 2 . 4 % `:. (Deltar)/(r) xx 100 = (Delta R)/(R) xx 100 + (Delta((I_(1))/(I_(2))))/(((I_(1))/(I_(2))))XX100 ` = 4 + 02 = 42% |
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