1.

In the diagram, ABD and BCD are isosceles triangles, where AB = BC= BD. The special name that is given to quadrilateral ABCD is:(a) rectangle (b) kite (c) parallelogram (d) trapezium

Answer»

(d) trapezium

In Δ BAD, 

∠ BDA=∠BAD= 57°        (isos. Δ property) 

In Δ BDC, 

∠BCD=∠BDC= 66°        (isos. Δ property) 

∴ ∠D = 57° + 66° = 123° and 

∠A +∠D = 57° + 123° = 180° 

Also, ∠D + C = 123° + 66° = 189° 

Hence, by the property that co-int. angles are supplementary ⇒ lines are parallel, we have AB || DC and AD not || BC. 

Hence ABCD is a trapezium.



Discussion

No Comment Found

Related InterviewSolutions