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In the displacement method, a convex lens is placed in between an obect and a screen. If the magnification in the two positions are m_(1) and m_(2) and the displacement of the lens between two positions is x, then the focal length of the lens is: |
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Answer» `(X)/(m_(1)+m_(2))` `(1)/(f) = (u-v)/(UV)` `(1)/(f)=((u-v)(v+u))/(uv(v+u))` `f = (uv(v+u))/(u^(2)-v^(2))` `therefore "" f=(v+u)/(u^(2)/(uv)-(v^(2))/(uv))=(u+v)/((u)/(v)-(v)/(u))` `therefore "" f = (x)/(m_(2) - m_(1))`. |
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