InterviewSolution
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InterviewSolution
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In the dissociation of HI, `20%` of HI is dissociated at equilibrium. Calculate `K_(p)` for `HI(g) hArr 1//2 H_(2)(g)+1//2 I_(2)(g)` |
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Answer» Correct Answer - A::B `{:(,2HI,hArr,1/2 H_(2),+,1/2 I_(2)),("Initial",1,,0,,0),("moles at Eq",(1-alpha),,alpha//2,,alpha//2):}` where `alpha` is degree of dissociation and volume of container is VL. `K_(p)=K_(c)((alpha/(2V))^(1//2)(alpha/(2V))^(1//2))/(((1-alpha))/V)` `K_(p)=K_(c)=alpha/(2(1-alpha))` `alpha=0.2` `K_(p)=K_(c)=0.2/(2(1-0.2))` `K_(p)=K_(c)=0.125` |
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