Saved Bookmarks
| 1. |
In the electric ntework shown in the figure, use Kirchhoffs rules to calculate the power consumed by the resistance R = 4Ω. |
|
Answer» SOLUTION :For LOOP ABCDA `-12 + 2I _(1) + 4 ( I _(1) + I _(2)) =0` `therefore 3I_(1) + 2I _(2) =6""…(i)` For loop ADFEA `-4 ( I _(1) + I _(2)) + 6=0` `therefore 2I _(1) + 2I_(2) =3""…(ii)` Solving (i) and (ii), we get `I _(1) = 3 A` `I _(2) =- 1. 5 A` Hence, power consumed by the resistor `R = ( I _(1) + I _(2)) ^(2) R` `= (1.5) ^(2) xx 4 =9 ` watt |
|