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In the electrochemical cell- Zn|ZnSO_(4)(0.01M)||CuSO_(4)(1.0M)|Cu, the emf of this Daniel cell is E_(1). When the concentration ofZnSO_(4) is changed to 1.0M and that of CuSO_(4) changed to 0.01M, the emf changes to E_(2). From the following , which one is the relationship between E_(1) and E_(2) ? (Given , (RT)/(F) = 0.059) |
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Answer» `E_(1) =E_(2)` |
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