Saved Bookmarks
| 1. |
In the electrochemical cell: Znabs(ZnSO_(4)(0.01M))abs(CuSO_(4)(1.0M))Cu, the emf of this Daniel cell is E_(1). When the concentration of ZNSO_(4) is changed to 1.0 M and that CuSO_(4) changed to 0.01M, the emf changes to E_(2). From the followings, which one is the relationship between E_(1) " and "E_(2)? |
|
Answer» `E_(1) LT E_(2)` |
|