1.

In the equation N_(2)+3H_(2) hArr 2NH_(3) the equality realationship between (d[NH_(3)])/(dt) and -(d[H_(2)])/(dt) is

Answer»

`+(d[NH_(3)])/(DT)=-(3)/(2)(d[H_(2)])/(dt)`
`(d[NH_(3)])/(dt)=-(d[H_(2)])/(dt)`
`(d[NH_(3)])/(dt)=-(1)/(3)(d[H_(2)])/(dt)`
`+(d[NH_(3)])/(dt)=-(2)/(3)(d[H_(2)])/(dt)`

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