1.

In the equilibrium, 2AhArrB+C, the equilibrium concentrations of A.B and C at 300K are 3xx10^(-4)M, 1xx10^(-4)M and 4.5xx10^(-4)M respectively. Thte vlue of K_(c) for the above equilibrium at 300 K is

Answer»

`0.5`
`0.05`
`5.0`
`1.5`

Solution :For the equlibrium,
`2AhArrB+C`
`K_(c)=([B][C])/([A]^(2))`
`where [B]=1XX10^(-4)M,[C]=4.5xx10^(-4)M and [A]=3XX10^(-4)M`
Then `k_(c)=((1xx10^(-4))(4.5xx10^(-4)))/((3xx10^(-4))^(2))=(4.5)/(9)=0.5`


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