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In the equilibrium, `2AhArrB+C,` the equilibrium concentrations of `A.B and C at 300K` are `3xx10^(-4)M, 1xx10^(-4)M and 4.5xx10^(-4)M` respectively. Thte vlue of `K_(c)` for the above equilibrium at 300 K isA. `0.5`B. `0.05`C. `5.0`D. `1.5` |
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Answer» Correct Answer - A For the equlibrium, `2AhArrB+C` `K_(c)=([B][C])/([A]^(2))` `where [B]=1xx10^(-4)M,[C]=4.5xx10^(-4)M and [A]=3xx10^(-4)M` Then `k_(c)=((1xx10^(-4))(4.5xx10^(-4)))/((3xx10^(-4))^(2))=(4.5)/(9)=0.5` |
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