1.

In the equilibrium CH_(3)COOH + HF hArr CH_(3)COOH_(2)^(+) + F^(-)

Answer»

`F^(-)` is the conjugate acid of `CH_(3)COOH`
`F^(-)` is the conjugate base of HF
`CH_(3)COOH` is the conjugate base of `CH_(3)COOH_(2)^(+)`
`CH_(3)COOH_(2)^(+)` is the conjugate base of `CH_(3)COOH`

Solution :`CH_(3)COOH + HF HARR CH_(3)COOH_(2)^(+) + F^(-)`. HF gives `H^(+)` to the `CH_(3)COOH`. So it is a conjugate base of HF.


Discussion

No Comment Found

Related InterviewSolutions