1.

In the estimation of chlorine in a given compound, it was found that 0.0811g of a compound gave 0.2368g of silver chloride. Calculate the percentage of chlorine in the given compound.(Ag= 108, Cl= 35.5)

Answer»

Solution :Moles of Cl in AgCl `= 1 xx` MOLE of AgCl
`=(0.2368)/(143.5)` (AgCl= 143.5)
Weight of CHLORINE `= (0.2368)/(143.5)xx 35.5`
0.0586g
PERCENTAGE of Cl in the compound `= (0.0586)/(0.0811) xx 100`
= 72.27%


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