1.

In the estimation of sulphur by Carius method, 0.480g of an organic compound gives 0.699g of barium sulphate. The percentage of sulphur in this compound is [Atomic masses : Ba=137, S=32, O=16]

Answer»

`20%`
`15%`
`35%`
`30%`

Solution :Percentage of `S=(32)/(233)xx("Mass of"BaSO_(4)"formed")/("Mass of compound taken")xx100`
`=(32)/(233)xx(0.699)/(0.480)xx100=20%`


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