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In the exp of finding sp heat capacity of an unknown sphere (S_(2)) mass of the sphere and caloreter aro 1000m and 200gm respectively and sp heat capacity of calorimeter is equal to (1)/(2)cal//gm^(@)C The mass of liquid 9water) used is 900gm Initially both the water and the calorimeter were at room temp 20.0^(@)C while used is 900gm Initially both the water and the calorimeter were at room temp 20.0^(@)C while the sphere was at temp 800^(@)C initially If the steady state temp was found to be 40.0^(@)C estimate sp heat capacity of the unknown sphere (S_(2)) (use S_(water) = 1 cal//g^(@)C) Also fin the maximum permissible error in sp heat capacity of unknown sphere (S_(2)) mass end specific heats of sphere and calorimater are correctly known) . |
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Answer» Solution :To DETERMINE the specitle heat CAPACITY of unkonw soild We USE`s_("SOLID")=(m_(1)s_(1)+m_(2)s_(2))/(m_(1))((0_(s)-0_(2))/(0_(1)-0_(s)))and" get "s_(solid)=1//2cal//g// .^(@)C` `((Deltas)/(s))_(max)=20Deltatheta((1)/(0_(s.s)-2_(2))+(1)/(0_(1)-0_(s s)))=2(0.1^(@)C)((1)/(40.0-20.0)+(1)/(80.0-40.0))=1.5%` . |
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